python list 内嵌列 表转为一维列表 https://blog.csdn.net/u010652755/article/details/105549848?ops_request_misc=%7B%22request%5Fid%22%3A%22160188046619195188364090%22%2C%22scm%22%3A%2220140713.130102334.pc%5Fall.%22%7D&request_id=160188046619195188364090&biz_id=0&utm_medium=distribute.pc_search_result.none-task-blog-2_allfirst_rank_ecpm_v3~pc_rank_v2-1-105549848.first_rank_ecpm_v3_pc_rank_v2&utm_term=内嵌列表转列表&spm=1018.2118.3001.4187

可以展开任意维的列表, 使用匿名函数 lambda

func = lambda x: [y for l in x for y in func(l)] if type(x) is list else [x]

a = [[1,2,3], [4,5,6], [7], [8,9], ‘c’] result = func(a)

python将一维列表转换为多维列表（numpy+reshape） https://blog.csdn.net/qq_28626909/article/details/81162560?utm_medium=distribute.pc_relevant.none-task-blog-BlogCommendFromMachineLearnPai2-1.nonecase&depth_1-utm_source=distribute.pc_relevant.none-task-blog-BlogCommendFromMachineLearnPai2-1.nonecase

python 纯数字list转化为字符串 在python中，如果将字符串类型的list转化为一个字符串 用 s=[“one”,“two”,“three”] ““join(s)就可以达到目的，而用 纯数字list s=[1,223,23] print(”,”.join(s)) TypeError: sequence item 0: expected str instance, int found 会出错，这样就得把list中的每个转为字符，如下：

s=[1,223,23] print(",".join(str(i) for i in s))

https://blog.csdn.net/chengyq116/article/details/89918640

https://blog.csdn.net/u013724573/article/details/72920924

https://blog.csdn.net/qq_39026556/article/details/82716207?utm_medium=distribute.pc_relevant_t0.none-task-blog-BlogCommendFromMachineLearnPai2-1.nonecase&depth_1-utm_source=distribute.pc_relevant_t0.none-task-blog-BlogCommendFromMachineLearnPai2-1.nonecase