习题5.9 C语言程序：求1000以内的完数并且并且按照以下格式输出因子： 6 its factors are 1,2,3 终于弄出来一个输出格式完全符合的啦
#include<stdio.h>
int main()
{
int i
,j
,k
;
int sum
=1;
printf("完数如下:");
for(j
=6;j
<1000;j
++)
{
sum
=1;
for(i
=2;i
<=j
/2;i
++)
{
if(j
%i
==0)
sum
=sum
+i
;
}
if(sum
==j
)
{
printf("\n%d its factors are:1",sum
);
for(k
=2;k
<=j
/2;k
++)
{
if(sum
%k
==0)
printf(",%d",k
);
}
}
}
printf("\n");
}
