求解一元二次方程ax^2+bx+c=0的根

#include <iostream> #include <string> //常用数学工具库 //官方网址 http://www.cplusplus.com/reference/cmath/ #include <cmath> using namespace std; //求解一元二次方程ax^2+bx+c=0的根 int main() { float a, b, c;//系数 float x1, x2; cout << "请输入a的值：" << endl; cin >> a; cout << "请输入b的值：" << endl; cin >> b; cout << "请输入c的值：" << endl; cin >> c; cout << "您输入的方程为：" << a << "x^2+" << b << "x+" << c << "=0" << endl; float t = b * b - 4 * a * c;//得塔 if (t < 0) { cout << "此方程无实数根" << endl; } else { //求根公式 x1 = (-b + sqrt(t)) / (2 * a);//sqrt(t):对t开平方 x2 = (-b - sqrt(t)) / (2 * a); cout << "一个根x1=" << x1 << endl; cout << "一个根x2=" << x2 << endl; } system("pause"); return 0; }

转载自：黑凤梨の博客