适用的数范围大(long long 型)复杂度相较于暴力判断较低
int isp(long long num)
{
if(num == 1) return 0;
if(num ==2|| num==3 ) return 1 ;
if(num %6!= 1&&num %6!= 5) return 0 ;
int tmp =sqrt( num);
for(int i= 5;i <=tmp; i+=6 )
{
if(num %i== 0||num %(i+ 2)==0 ) return 0 ;
}
return 1 ;
}
转载请注明原文地址:https://blackberry.8miu.com/read-2610.html