-- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

科技2023-12-28 96

SELECT st.s_id,st.s_name,AVG(sc.s_score) FROM student st LEFT JOIN score sc ON sc.s_id=st.s_id GROUP BY st.s_id HAVING AVG(sc.s_score)>=85

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