使用fastjson，将字符串转为map

1. 预先导入

/*json库 实体 <-> json*/ compile('com.alibaba:fastjson:1.2.51')

2. 实体类准备

package com.zr.domain; import lombok.Getter; import lombok.Setter; import java.sql.Date; import java.text.SimpleDateFormat; /** * 学生实体定义 * @author zhurui */ public class Student{ @Getter @Setter private long id; @Getter @Setter private long studentNumber; @Getter @Setter private String name; @Getter @Setter private String gender; @Getter @Setter private String studentClass; @Getter @Setter private java.sql.Date birthday; public Student(long id, long studentNumber, String name, String gender, String studentClass, Date birthday) { this.id = id; this.studentNumber = studentNumber; this.name = name; this.gender = gender; this.studentClass = studentClass; this.birthday = birthday; } @Override public String toString() { return "{" + "'id':'" + id + "'" + ", 'studentNumber':'" + studentNumber + "'" + ", 'name':'" + name + "'" + ", 'gender':'" + gender + "'" + ", 'studentClass':'" + studentClass + "'" + ", 'birthday':'" + new SimpleDateFormat("yyyy-MM-dd").format(birthday) + "'" + '}'; } }

注意

标准格式的json字符串,即{"k":"v","k":"v","k":"v"...............................}

3.调用

public HashMap getInfo() { return JSON.parseObject(student.toString(), HashMap.class); }

参考博客