实体:学生、老师
关系:学生多对一老师
实体(需要导入lombok依赖)
@Data @NoArgsConstructor @AllArgsConstructor @ToString public class Student { int id; String name; /** * 多个学生可以是同一个老师,即多对一 * Teacher teacher可以通过teacher类获取id * 简单的来说teacher.id要作为一个外键对象 */ private Teacher teacher; } @Data @NoArgsConstructor @AllArgsConstructor @ToString public class Teacher { int id; String name; }接口
/** * 实现增删改查的功能 * @author DELL */ public interface StudentMapper { /** * 多表查询 */ public List<Student> getStudent(); } /** * 老师表 */ public interface TeacherMapper { /** * 简单的查询 */ public List<Teacher> getTeacher(); }思路
1、查询所有的学生信息 2、根据查询出来的学生的tid,寻找对应的老师
映射文件(重点关注)
<select id="getStudent" resultMap="StudentTeacher"> select * from student </select> <!-- 这里的student需要去核心配置文件中设置别名--> <resultMap id="StudentTeacher" type="student"> <result property="id" column="id"/> <result property="name" column="name"/> <!-- 通过表象看本质,实质上就是解决数据库字段和属性名不一致的问题,用外键teacher作为一个对象,对象的类型javaType(主体)是teacher,由select=getTeacher查询得出的结果--> <!-- 复杂的属性,需要单独处理 对象:association 集合:collection--> <!-- javaType 为 student类中的 Teacher teacher--> <association property="teacher" column="tid" javaType="teacher" select="getTeacher"></association> </resultMap> <select id="getTeacher" resultType="teacher"> select * from teacher where id = #{id} </select>映射文件(重点关注)
<!--第二种方法--> <select id="getStudent" resultMap="StudentTeacher"> select student.id as sid,student.name as sname, teacher.name as tname from student,teacher where student.tid = teacher.id </select> <resultMap id="StudentTeacher" type="student"> <!-- proper为属性名 column为字段--> <result property="id" column="sid"/> <result property="name" column="sname"/> <!-- 关联对象property 关联对象在Student实体类中的属性,把teacher类中name关联给tname--> <association property="teacher" javaType="teacher" > <result property="name" column="tname"/> </association> </resultMap>实体:学生、老师
关系:老师一对多学生
实体
public class Student { int id; String name; int tid; public Student(){ } public Student(int id, String name, int tid){ this.id = id; this.name=name; this.tid = tid; } 。。get/set,toString方法 } public class Teacher { int id; String name; /** * 一个老师拥有多个学生 */ List<Student> students; public Teacher() { } public Teacher(int id, String name, List<Student> students) { this.id = id; this.name = name; this.students = students; } ....set/get方法,toString方法 }接口
public interface StudentMapper { /** * 多表查询 */ public List<Student> getStudent(); } public interface TeacherMapper { /** * 简单的查询 * 查询所有的老师 */ public List<Teacher> getTeacher(); /** *简单的查询单条记录 * 获取指定老师,及老师下的所有学生 */ public Teacher selectTeacherById(int n); }映射文件(需要重点关注)
<!--===================按结果查询--> <select id="selectTeacherById" resultMap="TeacherAndStudent"> select teacher.id as tid, teacher.name as tname,student.id as sid, student.name as sname from teacher, student where teacher.id=student.tid and teacher.id= #{id} </select> <resultMap id="TeacherAndStudent" type="teacher"> <result property="name" column="tname"/> <!-- 取集合里面的每一个值--> <collection property="students" ofType="student"> <result property="id" column="sid"></result> <result property="name" column="sname"></result> <result property="tid" column="tid"></result> </collection> </resultMap>扩展:
避免慢索引
必定面试问题
mysql引擎innoDB底层原理索引索引优化