2020-10-03

    科技2022-07-11  87

    python数学建模2019第一题代码

    # 导入模块 import pandas as pd import numpy as np import openpyxl # 读取数据 df1 = pd.read_csv(r'附件2.csv', encoding='gb18030') df2 = pd.read_csv(r'附件2.csv', encoding='gb18030') # 合并列表 frames = [df1, df2] result = pd.concat(frames, axis=0, join='outer') # 删除订单为0 result = result.drop(result[result['Order'] == 0].index) # 将成本价为0的设置为空值 result[result == 0] = np.nan # 计算成本价 result['Cost price'] = result['Cost price'].fillna(result['Price'] * 0.7) # 将Date设置为关键字 result['Date'] = pd.to_datetime(result['Date']) result = result.set_index('Date') # 生成2016-11-30到2019-1-2的每一天 index = [x.strftime('%Y-%m-%d') for x in list(pd.date_range(start='2016-11-30', end='2019-1-2'))] # 创建列表 T = [] for i in index: data = {} a = np.nansum(result[i]['Number'] * result[i]['Price']) b = np.nansum(result[i]['Number'] * result[i]['Cost price']) data['date'] = i data['Turnover'] = "{:.2f}".format(a) data['Total_cost'] = "{:.2f}".format(b) T.append(data) wb = openpyxl.Workbook() ws = wb.active head_row = ['日期', '营业额', '总成本'] ws.append(head_row) for data in T: data_row = [data['date'], data['Turnover'], data['Total_cost']] ws.append(data_row) wb.save('第一题数据.xlsx')
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