[leetcode] 1460. Make Two Arrays Equal by Reversing Sub-arrays

Description

Given two integer arrays of equal length target and arr.

In one step, you can select any non-empty sub-array of arr and reverse it. You are allowed to make any number of steps.

Return True if you can make arr equal to target, or False otherwise.

Example 1:

Input: target = [1,2,3,4], arr = [2,4,1,3] Output: true Explanation: You can follow the next steps to convert arr to target: 1- Reverse sub-array [2,4,1], arr becomes [1,4,2,3] 2- Reverse sub-array [4,2], arr becomes [1,2,4,3] 3- Reverse sub-array [4,3], arr becomes [1,2,3,4] There are multiple ways to convert arr to target, this is not the only way to do so.

Example 2:

Input: target = [7], arr = [7] Output: true Explanation: arr is equal to target without any reverses.

Example 3:

Input: target = [1,12], arr = [12,1] Output: true

Example 4:

Input: target = [3,7,9], arr = [3,7,11] Output: false Explanation: arr doesn't have value 9 and it can never be converted to target.

Example 5:

Input: target = [1,1,1,1,1], arr = [1,1,1,1,1] Output: true

Constraints:

target.length == arr.length1 <= target.length <= 10001 <= target[i] <= 10001 <= arr[i] <= 1000

分析

题目的意思是：判断arr数组能否通过逆序操作变成target数组，这里思路很直接，如果arr数组和target元素是一样的，肯定能够通过有限的操作变成target，否则就不能。知道了这个酒吧两个数组排序一下，然后遍历比较一下就能够得出结论。

代码

class Solution: def canBeEqual(self, target: List[int], arr: List[int]) -> bool: target.sort() arr.sort() for src,tar in zip(arr,target): if(src!=tar): return False return True