L1-064 估值一亿的AI核心代码 (20分)

#include <bits/stdc++.h> #define int ll //#pragma GCC optimize(2) using namespace std; typedef long long ll; const int maxn=1e5+10; void solve() { string str[1005]; int cnt=0; string s; getline(cin,s); cout<<s<<"\n"<<"AI:"; for (int i = 0; i < s.size(); ++i) { if (isupper(s[i])&&s[i]!='I') s[i]=tolower(s[i]); else if (!isalnum(s[i])) s.insert(i," "),i++; if (s[i]=='?') s[i]='!'; } stringstream ss(s); while (ss>>s) str[cnt++]=s; if (!isalnum(str[0][0])) cout<<" "; for (int i = 0; i < cnt; ++i) { if (!isalnum(str[i][0])) cout<<str[i]; else if ((str[i]=="can"||str[i]=="could")&&str[i+1]=="you")cout << " I " << str[i],i++; else if (str[i]=="I"||str[i]=="me") cout << " you"; else cout << " " << str[i]; } cout<<"\n"; } signed main() { //ios::sync_with_stdio(0), cin.tie(0), cout.tie(0); int _ = 1; cin >> _;getchar(); while (_--) { solve(); } return 0; } #include<bits/stdc++.h> using namespace std; int main() { int n; cin >> n; cin.get(); while (n--) { string s; getline(cin, s); cout << s << endl; for (char & c : s) { if (c >='A' && c <= 'Z' && c != 'I') { c = c - 'A' + 'a'; } } s = regex_replace(s, regex(" +"), " ");//消除多余空格 s = regex_replace(s, regex("^ | $"), "");//消除首尾空格 s = regex_replace(s, regex(" (\\W)"), "$1");//消除标点符号前的空格 s = regex_replace(s, regex("\\?"), "!");//将?替换成! s = regex_replace(s, regex("\\bcan you\\b"), "A");//转换can you s = regex_replace(s, regex("\\bcould you\\b"), "B");//转换could you s = regex_replace(s, regex("\\b(I|me)\\b"), "C");//转换I、me s = regex_replace(s, regex("A"), "I can"); s = regex_replace(s, regex("B"), "I could"); s = regex_replace(s, regex("C"), "you"); cout << "AI: " << s << endl; } return 0; }