建表语句点击详见
– 查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩
SELECT
st
.s_id
,
st
.s_name
,
AVG(sc
.s_score
)
FROM student st
LEFT JOIN score sc
ON sc
.s_id
=st
.s_id
GROUP BY st
.s_id
HAVING AVG(sc
.s_score
)>=85
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