LeetCode--614. 二级关注者

    科技2025-04-24  9

    解题思路

    第一个表的关注者是第二个表的被关注者,对第二个表的关注者计数

    select f1.follower,count(distinct f2.follower) as num from follow f1,follow f2 where f1.follower=f2.followee group by f1.follower select followee as follower,count(distinct follower) as num from follow where followee in (select follower from follow) group by followee
    Processed: 0.009, SQL: 8