Leetcode 26unique 使用

    科技2025-07-30  16

    思路:直接调用STL库函数  (简单但是肯定不会快)

    Vector中移除重复元素

     #include <algorithm>

    unique(nums.begin(), nums.end());//重复元素甩最后,返回的是最后一个非重复元素的后一个地址

    但是要记住:要先排序才能用

    sort(nums.begin(), nums.end());

    unique(nums.begin(), nums.end())

    size=unique(nums.begin(), nums.end()) - nums.begin();

    # include<iostream> # include<vector> # include<string> # include<algorithm> # include<math.h> # include<climits> # include<stack> # include<queue> using namespace std; int removeDuplicates(vector<int>& nums) { sort(nums.begin(), nums.end());//快排 int size = unique(nums.begin(), nums.end())-nums.begin();//唯一函数 return size; } int main(void) { vector<int> nums; nums.push_back(1); nums.push_back(1); nums.push_back(4); cout << removeDuplicates(nums) << endl; system("pause"); return 0; }

     

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