C++时间函数总结(含思维导图)

    科技2025-08-05  16

    一,时间函数知识点总结 二,计算程序运行时间的代码实例(本人课堂实例)

    #include <iostream> #include<ctime> //时间头文件 using namespace std; int main() { const int Count1 = 10; //声明常量 const int Count2 = 1000000;//声明常量 const int Count3 = 1000;//声明常量 int i,j; //声明变量 float sum = 0.0; time_t start_time, finish_time; //声明时间变量 clock_t time_req; //定义一个保存时间的变量 for(i=0;i<Count1; i++) //循环1 sum+=1.0/Count1; //求和1 cout << "The sum of the for - loop(COUNT=10) is : " <<sum << endl<<endl; //输出第一个求和结果 sum=0.0; for(i=0;i< Count2;i++) //循环2 sum+=1.0/Count2; //求和2 cout<< "The sum of the for -loop(COUNT=1000000) is : " << sum << endl<<endl; //输出第二个求和结果 time_req = clock();//对从开始到当前计时 time(&start_time);//当前时间(开始时间) sum = 0.0; for(i=0; i<Count3; i++)//循环 for(j=0; j<Count3;j++) sum+=(1.0/Count3)*(1.0/Count3); cout<< "The sum of the for-loop(COUNT=1000*1000) is : "<<sum<<endl; time(&finish_time); //当前时间与1970.01.01时间差(秒) cout << " Time required(time) = " << difftime(finish_time, start_time) << "seconds"<<endl;//求时间差(即执行循环所需时间) time_req = clock() - time_req;//运行的时间 cout<< "Time required(clock) = " << time_req << " clocks" <<endl;//输出循环运行时间,单位毫秒 cout<< "Time required(clock) = " << (float)time_req/CLOCKS_PER_SEC << "seconds" <<endl <<endl;//输出循环行时间,CLOCKS_PER_SEC表示一秒钟会有多少个时钟计时单位 time_req = clock();//对从开始到当前计时 sum = 0.0; for(i=0; i<Count2; i++)//循环 for(j=0; j<Count3; j++) sum+= (1.0/Count2)*(1.0/Count3);//求和 cout<< "The sum of the for -loop(COUNT=1000000*1000) is : " <<sum <<endl;//输出循环求和结果 time(&finish_time);//完成的系统时间 cout << "Time required(time) = " << difftime(finish_time, start_time) << "seconds" <<endl;//输出执行时间 time_req =clock() - time_req;//运行时间 cout<< "Time required(clock) = " << time_req << "clocks" <<endl;//输出运行时间,单位毫秒 cout<< "Time required(clock) = " << (float) time_req/CLOCKS_PER_SEC << "seconds" <<endl;//输出循环运行时间,单位秒 return 0; }
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