Leetcode 27 erase 用法

思路：直接调用STL函数，当然速度并不会太快

至于这两个函数的用法，这个里面有图解

Vector中删除元素

remove(v.begin(), v.end(), 99);  //remove有返回值 ， newEnd位置

iterator erase (iterator position);

iterator erase (iterator first, iterator last);//这个删除的范围是左闭右开

                       // erase the 6th element

myvector.erase (myvector.begin()+5);

                      // erase the first 3 elements:

myvector.erase (myvector.begin(),myvector.begin()+3);

# include<iostream> # include<vector> # include<string> # include<algorithm> # include<math.h> # include<climits> # include<stack> # include<queue> using namespace std; int removeElement(vector<int>& nums, int val) { nums.erase(remove(nums.begin(), nums.end(), val), nums.end()); return nums.size(); } int main(void) { vector<int> nums; nums.push_back(1); nums.push_back(1); nums.push_back(2); nums.push_back(3); nums.push_back(4); cout << removeElement(nums,1) << endl; system("pause"); return 0; }