稀疏数组的读取和存入

    科技2022-07-12  131

    public static void main(String[] args) { // TODO 自动生成的方法存根 int [][]array1=new int[11][11]; array1[1][2]=1; array1[2][3]=2; //输出原数组 System.out.println("输出原始的数组"); for (int[] ints : array1) { for (int anInt : ints) { System.out.print(anInt+"\t"); } System.out.println(); } //得到有效数字的个数 int sum=0; for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if(array1[i][j]!=0) { sum++; } } } System.out.println("有效数字总和为"+sum); //将有效数组存入稀疏数组中 int [][]array2=new int[sum+1][3]; array2[0][0]=11; array2[0][1]=11; array2[0][2]=sum; int count=0; for (int i = 0; i < array1.length; i++) { for (int j = 0; j < array1[i].length; j++) { if(array1[i][j]!=0) { count++; array2[count][0]=i; array2[count][1]=j; array2[count][2]=array1[i][j]; } } } //打印稀疏数组 for (int i = 0; i < array2.length; i++) { System.out.println(array2[i][0]+"\t"+array2[i][1]+"\t"+array2[i][2]); } //读取稀疏数组 int [][] array3=new int[array2[0][0]][array2[0][1]]; for (int i = 1; i < array2.length; i++) { array3[array2[i][0]][array2[i][1]]=array2[i][2]; } //打印 System.out.println("打印出存入的数组:"); for (int[] ints : array3) { for (int anInt : ints) { System.out.print(anInt+"\t"); } System.out.println(); } }
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