使用递归求1+11+111+1111+11111的值

    科技2026-02-09  2

    public class Recursive01 { public static void main(String[] args) { int i = functionB(4); System.out.println(i); } public static int functionA(int n){ if (n==0){ return 1; } else { return (int) (functionA(n-1)+Math.pow(10,n)); } } public static int functionB(int n){ if (n==0){ return 1; }else { return functionB(n-1)+functionA(n); } } }

    Processed: 0.019, SQL: 10